Question

Evaluate: $\frac{3^{-2}}{4^{-3}}$

Answer 1

it can be written as $\frac{ 4^{3} }{ 3^{2} }$ now it can be easily evaluated
$\frac{64}{9}$

Answer 2

When you take denominator value to numerator the power value becomes plus and same for numerator.

Therefore, 3^-2/4^-3 = 4^3/3^2 = 64/9