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ρℓєαѕє мαяк мє вяαιи ℓιѕт !!
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−−(1)Using property of definite integral:I(x)=I(−1+1−x)=I(−x)=∫1−1(sin3(−x).cos2(−x)) dx=∫1−1(−sin3(x).cos2(x)) dx −−−(2)Adding 1 and 2,2I=∫1−1(−sin3(x).cos2(x)+sin3(x).cos2(x)) dx 2I=∫1−1cos2(x)(sin3(x)−sin3(x))dx2I=∫1−1cos2(x).0I=0Hint : Solve remaining questions using this concept
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ρℓєαѕє мαяк мє вяαιи ℓιѕт !!
=========================
−−(1)Using property of definite integral:I(x)=I(−1+1−x)=I(−x)=∫1−1(sin3(−x).cos2(−x)) dx=∫1−1(−sin3(x).cos2(x)) dx −−−(2)Adding 1 and 2,2I=∫1−1(−sin3(x).cos2(x)+sin3(x).cos2(x)) dx 2I=∫1−1cos2(x)(sin3(x)−sin3(x))dx2I=∫1−1cos2(x).0I=0Hint : Solve remaining questions using this concept
Hope this information will clear your doubts about this topic.
If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.
Regards
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