Question

Evaluate

$\int_{x^2}^{x^3}{e}^{t}dt$

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Answer 1

hope it helps you out dude

Answer 2

ANSWER

$e^{x^{3} } - e^{x^{2} }$

Step By Step Explanation

As we are given here that we need to evaluate =>

$\int_{x^2}^{x^3}{e}^{t}dt$

On simplifying we get >

$\implies [e^{t}]_{x^{2} }^{x^{3} }$

$\implies e^{x^{3} } - e^{x^{2} }$

Hence the evaluation of $\int_{x^2}^{x^3}{e}^{t}dt$ will be $e^{x^{3} } - e^{x^{2} }$.