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Given, cos217+cos273sin263+sin227=cos2(17)+(cos(90−17))2sin263+(sin(90−63))2
As we know
90−63=27
90−17=73
from (sin(90−63)=cos63, cos(90−17)=sin17,
Now,
cos217+cos273sin263+sin227=cos2(17)+(cos(90−17))2sin263+(sin(90−63))2=cos217+sin217sin263+cos263
=11=1 ∵sin
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