Question

Evaluate the 0 to 1 integration x^2 /1+x^2 dx​

Answer 1

Answer:

x^2 plus one minus one divided by 1 + x square

then X square + 1 one is cancelled by 1 + x square and remains one plus minus 1 divided by 1 + x square

then the integration of 1 is x and the integration of 1 upon 1 + x square is tanx

then we put the limit 0 to 1

then the answer is is 1 - tan 1

Answer 2

Step-by-step explanation:

(x-tan^-1x)from 0to1 its answer is π/4-1