Question

evaluate the DX upon x^2+4x+5​

Answer 1

Answer:

x

2

−4x+13

dx

=∫

(x−2)

2

−4+13

dx

=∫

(x−2)

2

+(3)

2

dx

=

3

1

tan

−1

(

3

x−2

)+C

Hence ∫

x

2

−4x+13

dx

=

3

1

tan

−1

(

3

x−2

)+C