Evaluate the fol
following integra
[2x-1÷3√x]^2×dx
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Answer:
(2x-1/3√x)^2=4x^2-1/9x-4√x/3
int.(2x-1/3√x)^2= int. (4x^2-1/9x-4√x/3)
= 4x^3/3-(1/9)log x -8x^(3/2)/9:
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