Question

Evaluate the following

1. 9y + 3 if y is 3

2.9m^4 if m is 8

3.d^2 - 2d + d if d is 3

4. 6q + 30 if q is 5 ​

Answer 1

$Question \: -:$

$Evaluate \: the \: following \: -:$

$1) \: 9y + 3 \: \: (y = 3)$

$2) \: 9 {m}^{4} \: \: (m = 8)$

$3) \: {d}^{2} - 2d + d \: \: (d \: = 3)$

$4) \: 6q + 30 \: \: (q = 5)$

$\blue\star$ Answer -:

$1) \: Answer -: 30.$

$2) \: Answer -: 36864.$

$3) \: Answer -: 6.$

$4) \: Answer -: 60.$

Explanation -:

Since we already know the value of all the variables, therefore lets make all the questions proper using them.

To remove the variables, just replace them with the value given.

So, we get -:

$Questions \: -:$

$1) \: 9 \times 3 + 3 \: \: (Since \: y = 3)$

$2) \: 9 \times {8}^{4} \: \: (Since \: m = 8)$

$3) \: {3}^{2} - 2 \times 3 + 3 \: \: (Since \: d = 3)$

$4) \: 6 \times 5 + 30 \: \: (Since \: q = 5)$

We have successfully removed the variables, but we still have powers, so we have to remove them as well.

Now, lets start solving the questions one by one.

$Question \: 1 \: -:$

$9 \times 3 + 3$

$27 + 3$

$30 .$

$Question \: 2 \: -:$

This question has powers. 8 is raised to the power 4, so to evaluate it, just multiply 8 × 8 × 8 × 8. We get 4096.

Now, lets solve it -:

$9 \times {8}^{4}$

$9 \times 4096 \: \: (Since \: 8^4 = 4096)$

$36864$

$Question \: 3 \: -:$

This question has powers too. 3 is raised to the power 2, so to evaluate it, lets just multiply 3 × 3. We get 9.

Now, lets solve it -:

$9 - 2 \times 3 + 3 \: \: (Since \: 3^2 = 9)$

$9 - 6 + 3$

$3 + 3$

$6$

$Question \: 4 \: -:$

$6 \times 5 + 30$

$30 + 30$

$60$

$Hope \: it \: helps! \:$