Question

evaluate the following:
1. i^(7)
2. i^(51)
​

Answer 1

Step-by-step explanation:

we know that

i^1 = i

i^2= -1

i^3 = -i

i^4= 1

this is called i operation on numbers 1,2,3,4.

so now here,

i^7 = i^4. i^3 = 1* (-i)= -i

2.

now , write 4 series like :- 4,8,12,16,...like this , does 51 come in this series?

:- no , right. last term before 51 in this series is -

:- 4*12= 48.

so now 49 , 50, 51 , 52 is same four number as 1, 2 ,3,4 for i operation

i^51 = is same is i^3

so ans= -i