evaluate the following A3 + B3 + 3ab2 + 3a2b
Answers
Answered by
1
Answer:
(a+b) 3...................
Answered by
2
Answer:
-1 is the answer
Explanation:
Let y = a3 + b3 + 3ab2 + 3a2 b
Given, a = 2, b = -3
So, y = 23 + (-3)3 + 3 * 2 * (-3)2 + 3 * 22 * (-3)
=> y = 8 + (-27) + 3 * 2 * 9 + 3 * 4 * (-3)
=> y = 8 - 27 + 54 - 36
=> y = 8 + 54 - 27 - 36
=> y = 62 - 27 - 36
=> y = 35 - 36
=> y = -1
Hence, when a = 2, b = -3, then the value of a3 + b3 + 3ab2 + 3a2 b is -1
Similar questions