Evaluate the following at X=-1 y=-2 z=0 (X+y)2 - (y+z)2 -(x+z)2_3xyz
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Answered by
1
Answer:
1+a
2
−b
2
2ab
2b
2ab
1−a
2
+b
2
−2a
−2b
2a
1−a
2
−b
2
∣
∣
∣
∣
∣
∣
∣
∣
R
1
→R
1
+bR
3
∣
∣
∣
∣
∣
∣
∣
∣
1+a
2
+b
2
2ab
2b
0
1−a
2
+b
2
−2a
−b(1+a
2
+b
2
)
2a
1−a
2
−b
2
∣
∣
∣
∣
∣
∣
∣
∣
(1+a
2
+b
2
)
∣
∣
∣
∣
∣
∣
∣
∣
1
2ab
2b
0
1−a
2
+b
2
−2a
−b
2a
1−a
2
−b
2
∣
∣
∣
∣
∣
∣
∣
∣
R
2
→R
2
−aR
3
(1+a
2
+b
2
)
∣
∣
∣
∣
∣
∣
∣
∣
1
0
2b
0
1+a
2
+b
2
−2a
−b
a+a
3
+ab
2
1−a
2
−b
2
∣
∣
∣
∣
∣
∣
∣
∣
(1+a
2
+b
2
)
2
∣
∣
∣
∣
∣
∣
∣
∣
1
0
2b
0
1
−2a
−b
a
1−a
2
−b
2
∣
∣
∣
∣
∣
∣
∣
∣
Solving the above matrix, we get,
(1+a
2
+b
2
)
2
⋅(1+a
2
+b
2
)
(1+a
2
+b
2
)
3
Answered by
1
Answer:
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