Math, asked by sbraza078, 6 months ago

evaluate the following at x=-1,y=-2,z=0: (x+y+z)(x square+ y square+ z square- 2xy-2yz-2xz)​

Answers

Answered by BhaskarRouth
2

Answer:

-9

Step-by-step explanation:

(x+y+z)(x^2+y^2+z^2-2xy-2yz-2xz)

=x^3+y^3+z^3

=(-1)^3+(-2)^3+(0)^3. [when, x=-1, y=-2,=0]

=-1-8+0

=-9

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