Evaluate the following by using identity -I(i) 10.2 cube
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(10.2)^3=(10+0.2)^3.
= (10)^3+(0.2)^3+3(10)^2(0.2)+3(10)(0.2)^2
=1000+0.008+60+1.2
=1061.208
Ritiksuglan:
hi
Answered by
1
(10.2)^3=(10+0.2)^3
As we know that (a+b)^3=a^3+b^3+3a^2b+3ab^2
=10^3+(0.2)^3+3×(10)^2×0.2+3×10×(0.2)^2
=1000+0.008+60+1.2
=1061.208
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