Math, asked by sudhanshu4583, 11 months ago

Evaluate the following by using identity -I(i) 10.2 cube​

Answers

Answered by sumansagreeka043
2

(10.2)^3=(10+0.2)^3.

= (10)^3+(0.2)^3+3(10)^2(0.2)+3(10)(0.2)^2

=1000+0.008+60+1.2

=1061.208


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Answered by Sagreeka
1

(10.2)^3=(10+0.2)^3

As we know that (a+b)^3=a^3+b^3+3a^2b+3ab^2

=10^3+(0.2)^3+3×(10)^2×0.2+3×10×(0.2)^2

=1000+0.008+60+1.2

=1061.208

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