Question

Evaluate the following by using suitable identity ( ) 202×205 and
$99 {}^{2}$
​

Answer 1

$Value\: of \: 202\times 205$

$= ( 200 + 2 )(200 + 5 )$

/* By algebraic identity */

$\boxed{\pink{ (x+a)(x+b) = x^{2} + (a+b)x+ab }}$

$Here, a = 200, a = 2 \:and \: b = 5$

$= (200)^{2} + ( 2+5)\times 200 + 2 \times 5$

$= 40000 + 1400 + 10$

$= 41410$

Therefore.,

$\red{Product\: of \: 202\times 205}\green { = 41400}$

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Answer 2

Answer:

41410

Step-by-step explanation:

==: 202 * 205

==: (200 + 2) (200 + 5)

==: 40000 + 1000 + 400 + 10

==: 41410

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