Math, asked by bharatmonubaghel, 1 year ago

evaluate the following cos 47 cos13_ sin47 sin13

Answers

Answered by kushalpandey8858
0
I hope that it will help you
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kushalpandey8858: cos will be there
priyadharsan: yes
priyadharsan: but look at ur answer
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priyadharsan: pls correct it
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Answered by priyadharsan
3
cosAcosB - sinAsinB = cos(A+B).
So cos47cos13 - sin47sin13 = cos(47+13).
So the answer is cos(60) i.e. (1/2)
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