Question

evaluate the following expression for x = –2 and y = 4

Answer 1

Answer:

3y(2y−7)−3(y−4)−63

= 3y.2y−3y.7−3.y+3×4−63

=6y

2

−21y−3y+12−63

=6y

2

−24y−51.

for y=−2 in expression

6y

2

−24y−51=6(−2)

2

−24(−2)−51

=6(4)+48−51

=24+48−51

= 72−51

= 21.