Math, asked by ayushik761, 22 days ago

evaluate the following if a=3, b=2, c=1 a3+b3+c3-2ab

Answers

Answered by vihugarima25
0

Answer:

Algebra

Step-by-step explanation:

a3 = 9

b3 = 6

c3 = 3

2ab = 12

Answer = 6

Answered by Anonymous
7

Answer:

24

Step-by-step explanation:

We'll solve the above question by taking the variable as =

\rightarrow a= 3

\rightarrow b= 2

\rightarrow c= 1

‎ ‎

 {a}^{3}  +  {b}^{3}   +  {c}^{3}  - 2ab \\  \\  =  {3}^{3}  +  {2}^{3}  +  {1}^{3}  - 2(3 \times 2) \\  \\  = 27 + 8 + 1 - 12 \\  \\  = 27 +9- 12\\  \\  = 36-12 \\  \\  = 24

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