evaluate the following limit : Lt x tends to a asinx- xsina/ ax^2-xa^2
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Differentiate both upper and lower sides wrt x.
lim ( a cosx - sina )/ (2ax - a^2)
Now lim x->a,
Therefore,
Ans = a cosa - sina/(a)^2
lim ( a cosx - sina )/ (2ax - a^2)
Now lim x->a,
Therefore,
Ans = a cosa - sina/(a)^2
tokaians:
can you show with the method of limits
lim x->a means lim x-a -> 0 or if h = x-a
then lim h->0 where x = a+h
we use this substitution into the limit
then lim h->0 where x = a+h
we use this substitution into the limit
ughhh.. here its not possible to explain wholly
so can you edit the answer
yea but idk why the edit answer is not showing.. you've reported I think..
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