Question

evaluate the following postfix expression ABC*D/+ where A=2 B=3C=4D=6​

Answer 1

9×6

54

is the sln to ur question

Answer 2

4 is the postfix expression ABC×D÷+ when A=2, B=3, C=4, D=6 by stack and scanned symbols.

Given that,

We have to evaluate the postfix expression ABC×D÷+ when A=2, B=3, C=4, D=6.

We know that,

Take the postfix expression ABC×D÷+

In the postfix expression two steps are there

They are

Step1- when there is a number or variable we just take same

Step2- when there is an operation like +, -, ×, ÷ then we have to take the operation for the last two numbers or variables.

So,

ABC×D÷+

Symbol scanned      |       stack

            A                  |          A

            B                  |          A,B

            C                  |          A,B,C

            ×                   |         A,(B×C)

            D                  |         A, (B×C), D

             ÷                  |        A, $\frac{B\times C}{D}$

            +                   |          A+ $\frac{B\times C}{D}$

So,

A+ (($\frac{B\times C}{D}$) = 2+$\frac{3\times 4}{6}$

= 2+ $\frac{12}{6}$

= 2+ 2

=4

Therefore, 4 is the postfix expression ABC×D÷+ when A=2, B=3, C=4, D=6 by stack and scanned symbols.

To learn more about expression visit:

https://brainly.in/question/54139973

https://brainly.in/question/13401252

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