evaluate the following products without actual multiplication using algebric identities:-
1. 999*999
2.30.5*29.5
3.(50*1/2)*(49*1/2)
Answers
Answered by
55
1. 999*999
=(1000-1)*(1000-1)=(1000-1)∧2
=(1000)∧2+1∧2-2*1000*1
=1000000+1-2000
=998001
2. 30.5*29.5
=(30+ 0.5)*(30-0.5)
=(30)∧2-(0.5)∧2
=900-0.25
=899.75
3. (50*1/2)*(49*1/2)
=(50*49)*1/4
=(50*(50-1)*1/4
=(2500-50)*1/4
=2450/4
=1225
=(1000-1)*(1000-1)=(1000-1)∧2
=(1000)∧2+1∧2-2*1000*1
=1000000+1-2000
=998001
2. 30.5*29.5
=(30+ 0.5)*(30-0.5)
=(30)∧2-(0.5)∧2
=900-0.25
=899.75
3. (50*1/2)*(49*1/2)
=(50*49)*1/4
=(50*(50-1)*1/4
=(2500-50)*1/4
=2450/4
=1225
Answered by
11
Answer:
Step-by-step explanation:
(2x+y)(4x2-2xy+y2)
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