Question

If x=√2 is a solution of kx²+√2x-4=0 then find the value of k

Answer 1

Answer:

1

Step-by-step explanation:

Kx²+√2x-4=0

K(√2)²+√2(√2)-4=0

K(2)+2-4=0

2k-2=0

2k=2

K=2/2

Therefore k=1

Answer 2

Given:

x=√2 is a solution of kx²+√2x-4=0

To Find:

The value of k

Solution:

If x = √2 is a solution of the given equation,

Then √2 will satisfy the equation

so, when x = √2

⇒kx²+√2x-4 = 0

⇒k(√2)² + √2×√2-4 = 0

⇒2k + 2 -4 = 0

⇒2k - 2 = 0

⇒k = 1

Hence, the value of k is 1.