evaluate the following question number 11c)
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[ (0.4)³ - (0.24)³ ] / [ (0.4)² + 0.4 * 0.24 +(0.24)² ]
We know that a³ - b³ = (a-b)(a² + ab + b²)
=[(0.4 - 0.24)( (0.4)² + 0.4 * 0.24 + (0.24)² )] / [ (0.4)² + 0.4 * 0.24 +(0.24)²]
Since denominator is already in form a² + ab + b², the second bracket in numerator and the denominator get cancelled.
So, we have a - b left
= 0.4 - 0.24
= 0.16
We know that a³ - b³ = (a-b)(a² + ab + b²)
=[(0.4 - 0.24)( (0.4)² + 0.4 * 0.24 + (0.24)² )] / [ (0.4)² + 0.4 * 0.24 +(0.24)²]
Since denominator is already in form a² + ab + b², the second bracket in numerator and the denominator get cancelled.
So, we have a - b left
= 0.4 - 0.24
= 0.16
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Answered by
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Given [ (0.4)^3 - (0.24)^3 ] / [ (0.4)^2 + 0.4 * 0.24 +(0.24)^2 ]
this is in the form of { (a-b)(a^2+ab+b^2) }
= [(0.4 - 0.24)( (0.4)^2 + 0.4 * 0.24 + (0.24)^2 )] / [ (0.4)^2 + 0.4 * 0.24 +(0.24)^2]
= 0.4 - 0.24 ( remaining get canceled )
= 0.16 ....
hence solved
hope it's help u
this is in the form of { (a-b)(a^2+ab+b^2) }
= [(0.4 - 0.24)( (0.4)^2 + 0.4 * 0.24 + (0.24)^2 )] / [ (0.4)^2 + 0.4 * 0.24 +(0.24)^2]
= 0.4 - 0.24 ( remaining get canceled )
= 0.16 ....
hence solved
hope it's help u
hey dear no need of mark me best please my friends #purva thanks
hey answer is 0.16 by mistake i writen 0.20
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