Math, asked by sagarika77, 11 months ago

evaluate the following question

( \frac{3125}{243} )^ \frac { - 4}{5}

( \frac{81}{16} )^ \frac{ - 3}{4}  \times( ( \frac{9}{25})^ \frac{3}{2}  \div  (\frac{5}{2})^{ - 3} )


sagarika77: plzz solve it fast
sagarika77: it's tooo argent
sagarika77: plzzzz
sivaprasath: i) 81/625 , ii)1/729
sagarika77: what's the process
sagarika77: can you solve this plzzz☹️
sivaprasath: ok,
sagarika77: thanks

Answers

Answered by sivaprasath
4

Answer:

1) \frac{81}{625}

2) \frac{8}{27}

Step-by-step explanation:

Given :

To evaluate the following :

1)    ( \frac{3125}{243} )^ \frac { - 4}{5}

2)   ( \frac{81}{16} )^ \frac{ - 3}{4} \times( ( \frac{9}{25})^ \frac{3}{2} \div (\frac{5}{2})^{ - 3} )

Solution :

1)    ( \frac{3125}{243} )^ \frac { - 4}{5}

( \frac{5^5}{3^5} )^ \frac { - 4}{5}

(\frac{5}{3})^{5(\frac { - 4}{5})}

(\frac{5}{3})^{-4}

(\frac{3}{5})^{4}

(\frac{3^4}{5^4})

(\frac{81}{625})

( \frac{3125}{243} )^ \frac { - 4}{5} = (\frac{81}{625})

_

2)   ( \frac{81}{16} )^ \frac{ - 3}{4} \times( ( \frac{9}{25})^ \frac{3}{2} \div (\frac{5}{2})^{ - 3} )

( \frac{3^4}{2^4} )^ \frac{ - 3}{4} \times( ( \frac{3^2}{5^2})^ \frac{3}{2} \div (\frac{5}{2})^{ - 3} )

( \frac{3}{2} )^{4(\frac{ - 3}{4}) }\times( ( \frac{3}{5})^{2(\frac{3}{2})} \div (\frac{2}{5})^{ 3} )

( \frac{3}{2} )^{ - 3}\times( ( \frac{3}{5})^{3}} \div (\frac{2}{5})^{ 3} )

( \frac{2}{3} )^{3}\times( ( \frac{3}{5})^{3}} \times (\frac{5}{2})^{ 3} )

( \frac{2^3}{3^3} )\times( ( \frac{3^3}{5^3})} \times (\frac{5^3}{2^3}))

⇒ 1

( \frac{81}{16} )^ \frac{ - 3}{4} \times( ( \frac{9}{25})^ \frac{3}{2} \div (\frac{5}{2})^{ - 3} ) =1


sagarika77: thank you so much
sagarika77: ,really thank u so so much
sivaprasath: :-)
sagarika77: i think that you solve the second question wrong
sagarika77: because
sagarika77: in fourth step you wrote 5/3 but it actually 2/5
sagarika77: can you explain me how it is possible
sagarika77: and doen
sagarika77: done
sivaprasath: yeah, it's done,. typing mistake because my computer hanged while typing the 2nd Question's answer,.
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