Question

niobium is found to crystallise with BBC structure and found to have density of 8.55g cm-3 determine the atomic radius of niobium if its atomic mass is 93 (14.29nm)​

Answer 1

Answer:

Explanation:

Given Density = 8.55 gcm-3

Let the length of the edge = a cm

Number of atoms per unit cell, Z = 2

Atomic mass M = 93 u

From the formula , density = ZxM/a3 x N0, we get

8.55 = 2 x 93/a3 x 6.022 x 1023 = 36.12 x 10-24 cm3

Now edge length,a = (36.12 x 10-24)1/3 = 3.306 x 10-8 cm

Now radius in body centered cubic, r = √3/4 a

Putting the value of a, we get .r = 1.431 x 10-10 m