Math, asked by Anonymous, 6 months ago

Evaluate the following:

sin60⁰ cos30⁰ + sin30⁰ cos60⁰​

Answers

Answered by Anonymous
18

Putting the values of all the trigonometric ratio of 0⁰,30⁰,45⁰, 60⁰ and 90⁰

 \frac{ \sqrt{3} }{2}  \times  \frac{ \sqrt{3} }{2}   + \frac{1}{2}  \times  \frac{1}{2}

 \frac{3}{4}  +  \frac{1}{4}

Now taking L.C.M

L.C.M is 4

 \frac{3 + 1}{4}

 \frac{4}{4}

1

Additional Information:

The values of all the trigonometric ratio of 0⁰,30⁰,45⁰, 60⁰ and 90⁰are in the table given above in attachment which is used in solving these questions.

Attachments:
Answered by KrishJethwani40
1

Answer:

Putting the values of all the trigonometric ratio of 0⁰,30⁰,45⁰, 60⁰ and 90⁰

\frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} + \frac{1}{2} \times \frac{1}{2}

2

3

×

2

3

+

2

1

×

2

1

\frac{3}{4} + \frac{1}{4}

4

3

+

4

1

Now taking L.C.M

L.C.M is 4

\frac{3 + 1}{4}

4

3+1

\frac{4}{4}

4

4

11

Additional Information:

The values of all the trigonometric ratio of 0⁰,30⁰,45⁰, 60⁰ and 90⁰are in the table given above in attachment which is used in solving these questions.

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