evaluate the following using identities 102 cube
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(100+2)^3
we know(a+b)^3=a3+b3+3ab(a+b)
(100)3+(2)3+3(100)(2)(100+2)
1000000+8+600(102)
ans will be 1061208
we know(a+b)^3=a3+b3+3ab(a+b)
(100)3+(2)3+3(100)(2)(100+2)
1000000+8+600(102)
ans will be 1061208
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