evaluate the following using suitable identities 99 whole cube
Answers
Answered by
8
(100-1)²
=10000+1-200
=10001-200
=9801
=10000+1-200
=10001-200
=9801
Anonymous:
The question is(99)^3 not (99)^2
Answered by
17
(99)^3=(100-1)^3
Using identity--(a-b)^3=a^3-3a^2b+3ab^2-b^3
A=100
B=1
=(100)^3-3×(100)^2×1+3×100×(1)^2-(1)^3
=1000000-3×10000×1 + 3×100×1-1
=1000000-30000+300-1
=970299
Hey friend hope this answer helps you....^^
Plz mark as brainliest plz plzzz
Using identity--(a-b)^3=a^3-3a^2b+3ab^2-b^3
A=100
B=1
=(100)^3-3×(100)^2×1+3×100×(1)^2-(1)^3
=1000000-3×10000×1 + 3×100×1-1
=1000000-30000+300-1
=970299
Hey friend hope this answer helps you....^^
Plz mark as brainliest plz plzzz
Hey mark it as brainliest plz
Similar questions