Math, asked by PragyaTbia, 1 year ago

Evaluate the function w.r.t.x \int (3 x^{2} -5)^{2}dx

Answers

Answered by abhishek3068
0
this is the answer of this question
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Answered by sk940178
0

Answer:

\dfrac {9x^5}5 + 25x -{10x^3}+C

Step-by-step explanation:

We have to find the integration of \int (3x^2 - 5)^2 dx

So,

\int (3x^2 -5)^2 dx

By the formula of (a - b)^2

{(a-b)^2 = a^2 +b^2 -2ab}

(3x^2 - 5)^2 = (3x^2)^2 + 5^2 - 2 \times 3x^2 \times 5\\(3x^2 - 5)^2 = 9x^4 + 25 - 30x^2

\int (9x^4 + 25 -30x^2)dx\\9\int x^4dx + 25\int dx - 30\int x^2dx

\dfrac {9x^5}5 + 25x -{10x^3}+C

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