Question

Find the approximate value of x⁴ + 2x² + 3 at x = 2.01

Answer 1

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Answer 2

Answer:

27.4

Step-by-step explanation:

In the given question,

We have been provided the equation,

$f(x)=x^{4}+2x^{2}+3$

Now, we need to find the value of the function at x = 2.01.

So, on putting the value of x = 2.01, we get,

$f(2.01)=2.01^{4}+2(2.01)^{2}+3\\f(2.01)=16.322+8.080+3\\f(2.01)=27.402$

Therefore, the approximate value of the function at x = 2.01, is given by,

f(2.01) = 27.402 ≈ 27.4

Therefore, the approximate value of the function at x = 2.01 is 27.4