evaluate the given equation:(2y-1)(2y+1)(4y²+1)..
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Answer: 16y^4 - 1
Step-by-step explanation:
(2y - 1)(2y + 1)(4y²+1)
(4y²-1)(4y²+1)
= 16y^4 - 1. (Ans.)
Formulas used
(a+b)(a-b) = a² - b²
Thanks!
I hope that makes sense.
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