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Sin^2 63°+Sin^2 27°/Cos^2 17°+ Cos^2 73°
we know that
Sin(90-tetha)=cos tetha
Cos(90-tetha)=Sin tetha...
(Sin27°=cos63°
Cos73°=Sin17°)..
Sin^2 63°+cos^2 63°/Cos^2 17°+Sin^2 17°
{Sin^2tetha+Cos^2 tetha=1}
=1/1
=1
hope this helps you!
cheers ! (:
we know that
Sin(90-tetha)=cos tetha
Cos(90-tetha)=Sin tetha...
(Sin27°=cos63°
Cos73°=Sin17°)..
Sin^2 63°+cos^2 63°/Cos^2 17°+Sin^2 17°
{Sin^2tetha+Cos^2 tetha=1}
=1/1
=1
hope this helps you!
cheers ! (:
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