Physics, asked by khan3774, 1 year ago

evaluate the ∫ sin (2x^2) dx

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Answered by Anonymous

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Answered by Anonymous

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$Let \: I =∫ \sin( {2x}^{2} ) dx$

$= \frac{ - \cos( {2x}^{2} ) }{ \frac{d}{dx}( {2x}^{2}) } + C \\ = \frac{ - \cos( {2x}^{2} ) }{4x} +C$

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evaluate the ∫ sin (2x^2) dx