Question

if x:y=3:4, let us find (3y–x):(2x+y).​

Answer 1

x : y = 3 : 4

___________ [ GIVEN ]

• We have to find the ratio of (3y - x) : (2x + y).

____________________________

→ x : y = 3 : 4

$\dfrac{x}{y}$ = $\dfrac{3}{4}$

We can write above equation like that also,

Let $\dfrac{x}{3}$ = $\dfrac{y}{4}$ = M (here M is the assumed number)

Now;

→ $\dfrac{x}{3}$ = M

→ x = 3M

Similarly,

$\dfrac{y}{4}$ = M

→ y = 4M

Now put value of x and y in this :

(3y - x) : (2x + y).

→ $\dfrac{3y\:-\:x}{2x\:+\:y}$

→ $\dfrac{3(4M)\:-\:3M}{2(3M)\:+\:4M}$

→ $\dfrac{12M\:-\:3M}{6M\:+\:4M}$

→ $\dfrac{9M}{10M}$

M throughout cancel

→ $\dfrac{9}{10}$

→ 9 : 10

_____________________________

(3y - x) : (2x + y) = 9 : 10

________ [ ANSWER ]

_____________________________

Answer 2

The correct answer is $\frac{9}{10}$.

Given: The ratio of x and y = x:y=3:4.

To Find: The ratio = $\frac{3y - x}{2x+y}$.

Solution:

x:y=3:4.

Let the value of x = 3k.

Let the value of y = 4k.

$\frac{3y - x}{2x+y}=\frac{3(4k)-3k}{2(3k)+4k}$

= $\frac{9k}{10k}$

= $\frac{9}{10}$

Hence, the ratio is $\frac{9}{10}$.

#SPJ2