Question

Evaluate the
the integral:
Sin2x/(a²-cos²x+b²+sin²x) dx​

Answer 1

Answer:

integral sin(2 x)/(a^2 - cos^2(x) + b^2 + sin^2(x)) dx = 1/2 log(a^2 + b^2 - cos(2 x)) + constant

Step-by-step explanation:

look at attached image