Question

evaluate this √-1 ^192​

Answer 1

1 because 1^x is always equal to 1

Answer 2

Evaluation is $(\sqrt{-1})^{192}=1$

Step-by-step explanation:

Given : Expression $(\sqrt{-1})^{192}$

To find : Evaluate the expression ?

Solution :

We know that, $\sqrt{-1}=i$

So, $(\sqrt{-1})^{192}=(i)^{192}$

$(\sqrt{-1})^{192}=(i)^{2\times 96}$

$(\sqrt{-1})^{192}=(i^2)^{96}$

$(\sqrt{-1})^{192}=(-1)^{96}$

1 to the power of even number is always 1.

$(\sqrt{-1})^{192}=1$

Therefore, evaluation is $(\sqrt{-1})^{192}=1$

#Learn more

evaluate : 1• (64)^-1/

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