in a triangle ABC if angle A minus Angle B equal to 40 degree and Angle B minus angle c equal to 10 degree find the measure of Angle A Angle B and angle C
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let angle A=x
angle B=x-40°
angle C=x-50°
in triangle sum of all angles is 180°
x+x-50°+x-40°=180°
3x-90°=180°
3x=270°
x=90°
angle A=90°
B=50°
C=40°
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