Question

evaluate this.......

Answer 1

heya

______________________________

R.H.L

lim √( 1 + 0 + h ) - 1 / ( 0 + h )

h–>0

=>

lim √( 1 + h ) -1 / ( h )

h–>0

USING L'HOSPITALS RULE

lim 1/2√( 1 + h )

h–>0

= 1/2

L.H.L

lim √( 1 + 0 - h ) - 1/ ( 0 - h )

h–>0

=>

lim √( 1 - h ) / ( - h )

h–>0

=>

USING L'HOSPITALS RULE

lim -1/2√{1 - h }

h–>0

= -1/2

L.H.L ≠ R.H.L

So, limit doesn't exist.

Answer 2

welcome to the concept of limits .

⏩yr answer is 1/2

⏩I hope it help you ❤️