evaluate this question for me
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5
2 cos 67/sin 23 - tan 40/cot 50 - cos 30
=> 2 sin (90-67)/sin 23 -tan40/tan (90-50) -cos30
=>2 sin23/sin23 -tan40/tan40 -cos 30
=> 2 -1- root3/2
=>1-root3/2
=>2/2-root3/2
=>
=> 2 sin (90-67)/sin 23 -tan40/tan (90-50) -cos30
=>2 sin23/sin23 -tan40/tan40 -cos 30
=> 2 -1- root3/2
=>1-root3/2
=>2/2-root3/2
=>
Anonymous:
hope it will help u
hi
Answered by
4
2sin(90-67)/sin23-cot(90-40)/cot50-cos30
2*1-1-√3/2
1-√3/2
2-√3/2
2*1-1-√3/2
1-√3/2
2-√3/2
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