Question

Evaluate {under root 200} + {under root 621}+ under root 16

Answer 1

√200 + √621 + √16

√(10×10×2) + √(3×3×3×2×23) + √(4×4)

10√2 + 3√138 + 4


I hope this will help you

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Answer 2

Answer:

$10\sqrt{2}+3\sqrt{69}+4$

Step-by-step explanation:

We have been given that $\sqrt{200}+\sqrt{621}+\sqrt{16}$

Let us write each term as a perfect square so that we can cancel out the square with the square root.

200 = 100×2 = 10^2×2

621 = 3 x 3 x 3 x 23 = 3^2 x 69

16 = 4 x 4 = 4^2

Thus, we have

$\sqrt{10^2\times2}+\sqrt{3^2\times69}+\sqrt{4^2}\\=10\sqrt2+3\sqrt{69}+4$