Question

evaluate under root 48 upon under root 243

Answer 1

Answer:

4/9 is the answer friend

Answer 2

Answer:

Step-by-step explanation:

Concept:

The other number that, when multiplied by itself a predetermined number of times, equals $x$ is the root of the number$x$.

For instance, the third root of $64$, often known as the cube root, is$4$, since $64$ is equal to three times three fours multiplied together:

$4 * 4 * 4 = 64$

The above would be written as,

$\sqrt[3]{64} =4$

"the third root of $64$ is $4$" or "the cube root of $64$ is $4$" when spoken.

• The "square root" is the common name for the second root.
• Typically, the "cube root" is used to describe the third root of an integer.
• They are thus referred to as the $nth$ root, for instance the $5th$  root, $7th$ root, etc.

Given:

$\frac{\sqrt{48} }{\sqrt{243} }$

To Find:

Evaluate $\frac{\sqrt{48} }{\sqrt{243} }$

Solution:

Given that $\frac{\sqrt{48} }{\sqrt{243} }$

$\sqrt{48} =\sqrt{6*8}$

$\sqrt{48}=\sqrt{3*4*4}$

$\sqrt{48} =4\sqrt{3}$

$\sqrt{243} =\sqrt{81*3}$

$\sqrt{243} =9\sqrt{3}$

$\frac{\sqrt{48} }{\sqrt{243} } =\frac{4\sqrt{3} }{9\sqrt{3} }$

$\frac{\sqrt{48} }{\sqrt{243} } =\frac{4}{9}$

Hence $\frac{\sqrt{48} }{\sqrt{243} } =\frac{4}{9}$

#SPJ2