Question

evaluate using identities (3x+4/y)³ pls tell me fast​

Answer 1

Answer:

27x^2+64/y^3 + 108x^2/y+144x/y2

Step-by-step explanation:

(a+b)^3= a3+b3+3ab(a+b)

(3x)3 +(4/y)3+3*3x*4/y(3x+4/y)

27x^2 +64/y^3+36x/y*3x+36x/y*4/y

= 27x^2+64/y^3 + 108x^2/y+144x/y2,

I HOPE YOU FOUND IT HELPFUL