Question

evaluate using identity 103 ×107

Answer 1

(x+a) (x+b) = (x)^2 + (a+b)x + (ab)

(100+3) (100+7)
= (100)^2 + (7+3)100 + (7)(3)
= 10000 + 1000 + 21
= 11021

Hope this helps... plsss make it the brainliest

Answer 2

Answer:

Step-by-step explanation:

103×107

=(100+3)(100+7)=100^2+(3+7)*100+3*7

[By. , (X+a)(x+b)=x^2+(a+b)x+ab]

=10000+1000+21

=11021

Hope it helps you..pls mark as brainliest