Question

Evaluate using identity (24)³+(-18)³+(-6)³

Answer 1

Use the identity

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + { b}^{2} + {c}^{2} - ab - bc - ca)$
and solve

Answer 2

if sum of bases a,b,c is zero then the sum of their cubes = 3abc
here a=24
b=-18
c=-6
a+b+c=24-18-6=0
so their sum = 3*(-18)*(-6)=324

hope this helps you
pls mark brainliest