Question

Evaluate using identity: 37×26

Answer 1

Answer:

=(30+7) (30-4)

=30²+(7-4) (30) - 7×4

=900+90-28

=990-28

=962

Answer 2

The answer is, that 37x26 is 962.

that 37x26 is 962. Given:-

37x26

To Find:-

Evaluate the answer using the suitable property.

Solution:-

To find the answer, you should follow these simple steps as follows.

We have the identity as,

(x+a) (x+b) = x² + a*b + (a+b)*x

Also, we can write 37 as (30 + 7) and 26 as (30-4).

So, here after comparing,

x = 30

a = 7

b = -4

Now, put the values of x, a, and b in the equation.

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$$(x + a)(x + b) = {30}^{2} + (7 \times ( - 4)) + (7 + ( - 4)) \times 30$

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$$(x + a)(x + b) = {30}^{2} + (7 \times ( - 4)) + (7 + ( - 4)) \times 30$$(x + a)(x + b) = 900 + ( - 28) + 90$

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$$(x + a)(x + b) = {30}^{2} + (7 \times ( - 4)) + (7 + ( - 4)) \times 30$$(x + a)(x + b) = 900 + ( - 28) + 90$$(x + a)(x + b) = 990 - 28$

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$$(x + a)(x + b) = {30}^{2} + (7 \times ( - 4)) + (7 + ( - 4)) \times 30$$(x + a)(x + b) = 900 + ( - 28) + 90$$(x + a)(x + b) = 990 - 28$$(x + a)(x + b) = 962$

$( x+a)( x+ b) = {x}^{2} + (a\times b) + ( a + b) \times x$$(x + a)(x + b) = {30}^{2} + (7 \times ( - 4)) + (7 + ( - 4)) \times 30$$(x + a)(x + b) = 900 + ( - 28) + 90$$(x + a)(x + b) = 990 - 28$$(x + a)(x + b) = 962$Hence, 37x26 is 962.

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