evaluate using identity
(3x-4y+5z)²
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Answer:
9x²+16y²+25z²-24xy-40yz+30xz
Step-by-step explanation:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca is the identity.
by using this identity
a=3x
b=-4y
c=5z
(3x)²+(-4y)²+(5z)²+2(3x)(-4y)+2(-4y)(5z)+2(5z)(3x)
9x²+16y²+25z²-24xy-40yz+30xz
Note : (-x)²=x² not -x²
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