Math, asked by chittamaji74, 1 month ago

evaluate using identity
(3x-4y+5z)²​

Answers

Answered by rishabhshah2609
2

Answer:

9x²+16y²+25z²-24xy-40yz+30xz

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca is the identity.

by using this identity

a=3x

b=-4y

c=5z

(3x)²+(-4y)²+(5z)²+2(3x)(-4y)+2(-4y)(5z)+2(5z)(3x)

9x²+16y²+25z²-24xy-40yz+30xz

Note :  (-x)²=x² not -x²

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