Question

evaluate using suitable identities (1.93)³+(0.07)³-(2)³

Answer 1

This is an illustration of the identity

${a}^{3} \: + {b}^{3} + {c}^{3} = 3abc \\ if \: a + b + c = 0$

Here, a = 1.93

b = 0.07

c = 2

Here a+b+c=1.93+0.07-2 = 2-2 = 0

Therefore, we can use this identity and the answer = 3×1.93×0.07×2 = 0.8106

Hope this is helpful to you...

Pls mark as brainliest....

Answer 2

Answer:

a^3+b^3+c^3 is identity we used

Step-by-step explanation:

a is substituded with 1.93

b is substituded with 0.07

c is substituded with 2

3(1.93 X 0.07 X 2)

= 0.8106