evaluate using suitable identities A)105 × 95 B) 53 × 51
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i)first -
105=100+5
(100+5)×(100-5)
105× 100 + 105×5
10500+525
11025
ii) 53×51
= 53×(50+1)
=1650+53
1703
hope it helps please mark as brainliest have a bright future ahead
105=100+5
(100+5)×(100-5)
105× 100 + 105×5
10500+525
11025
ii) 53×51
= 53×(50+1)
=1650+53
1703
hope it helps please mark as brainliest have a bright future ahead
amansinghx13:
Can u explain how did u do the second one
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