Question

Evaluate using suitable identities
cube of (102)​

Answer 1

Answer:

$= > {(102)}^{3} \\ using \: identity \: {(a + b)}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b) \: we \: get... \\ = > {(100 + 2)}^{3} \\ = > {(100)}^{3} + {(2)}^{3} + 3 \times 100 \times 2(100 + 2) \\ = > 1000000 + 8 + 600(100 + 2) \\ = > 1000000 + 8 + 60000 + 1200 \\ = > 1061208</p><p></p><p></p><p></p><p>$

HOPE THIS HELPS YOU!! ✌❤☺✔️

Answer 2

Answer:

(102)³

=102×102×102

=(100+2)×(100+2)×(100+2)

=(100×100+100×2+2×100+2×2)×

(100+2)

=(10000+400+4)×(100+2)

=10404×(100+2)

=10404×100+10404×2

=1040400+20808

=1061208

I hope it will help you.