Question

Evaluate using suitable identity (1) 101

Answer 1

identity-

(a+b)² = a² + 2ab + b².

101=100+1

Let, a=100 ; b=1

(100+1)² = 100² + 2×100×1 + 1²

= 10000+200+1

= 10201

Thus, answer = 10201.