Math, asked by TheHeroOfTheWorld, 1 year ago

Evaluate using suitable identity

(52)²
(49)²
(103)²
(98)²
(1005)²

Answers

Answered by MiniDoraemon
74
Q. Evaluate using suitable identities :

(i) (52)²

Using the identity
=> (a+b)² = a² + 2ab + b²

(52)² = (50+2)²
= (50)² + 2×50×2 + (2)²
= 2500 + 200 + 4
= 2704

===================================

(ii) (49)²

Using the identity
=> (a-b)² = a² - 2ab + b²

(49)² = (50 – 2)²
= (50)² - 2×50×1 + (1)²
= 2500 – 100 + 1
= 2401

===================================

(iii) (103)²

Using the identity
=> (a+b)² = a² + 2ab + b²

(103)² = (100 + 3)²
= (100)² + 2×100×3 + (3)²
= 10000 + 600 + 9
= 10609

===================================

(iv) (98)²

Using the identity
=> (a-b)² = a² - 2ab + b²

(98)² = (100 – 2)²

= (100)² - 2×100×2 + (2)²
= 10000 – 400 + 4
= 9604

===================================

(v) (1005)²

Using the identity
=> (a+b)² = a² + 2ab + b²

(1005)² = (1000 + 5)²
= (1000)² + 2×1000×5 + (5)²
= 1000000 + 10000 + 25
= 1010025
Answered by thakur86
29

Answer:

heya✌✌

Step-by-step explanation:

(i) (52)²

Using the identity

=> (a+b)² = a² + 2ab + b²

(52)² = (50+2)²

= (50)² + 2×50×2 + (2)²

= 2500 + 200 + 4

= 2704

===================================

(ii) (49)²

Using the identity

=> (a-b)² = a² - 2ab + b²

(49)² = (50 – 2)²

= (50)² - 2×50×1 + (1)²

= 2500 – 100 + 1

= 2401

===================================

(iii) (103)²

Using the identity

=> (a+b)² = a² + 2ab + b²

(103)² = (100 + 3)²

= (100)² + 2×100×3 + (3)²

= 10000 + 600 + 9

= 10609

===================================

(iv) (98)²

Using the identity

=> (a-b)² = a² - 2ab + b²

(98)² = (100 – 2)²

= (100)² - 2×100×2 + (2)²

= 10000 – 400 + 4

= 9604

===================================

(v) (1005)²

Using the identity

=> (a+b)² = a² + 2ab + b²

(1005)² = (1000 + 5)²

= (1000)² + 2×1000×5 + (5)²

= 1000000 + 10000 + 25

= 1010025

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